Pure N_2 is not produced when | vedclass

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(D) $1$. The reaction of $NH_3$ with red hot $CuO$ is: $3CuO + 2NH_3 \xrightarrow{\Delta} 3Cu + N_2 + 3H_2O$. This reaction produces $N_2$ gas.$2$. Th

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) $1$. The reaction of $NH_3$ with red hot $CuO$ is: $3CuO + 2NH_3 \xrightarrow{\Delta} 3Cu + N_2 + 3H_2O$. This reaction produces $N_2$ gas.$2$. The thermal decomposition of sodium azide $(NaN_3)$ is: $2NaN_3 \xrightarrow{\Delta} 2Na + 3N_2$. This is a standard method for the preparation of very pure $N_2$.$3$. The thermal decomposition of barium azide $(Ba(N_3)_2)$ is: $Ba(N_3)_2 \xrightarrow{\Delta} Ba + 3N_2$. This is also a standard method for the preparation of very pure $N_2$.$4$. Since all the given reactions produce $N_2$,the correct answer is that none of these options fail to produce $N_2$.

Pure $N_2$ is not produced when

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